Hahaha this is a direct copy of the answer Omar gave me when I asked the chances of overshoot when intégrating that function
As for a question whether it will overshoot, It will not as it uses an exponential integrator with the assumption that p and A are static through the timestep: `A(t) = G + (A(0) – G) * e^(-pt)` the pull operation ends up evaluating the `A(t)` `A(0)` would be the current value of the field `G` is the current value of the source `p` is the strength Finally, `t` we are evaluating at is `TimeInc` For `t>0` and `p>0` (which is certainly the case), we can see that `0 < e^(-pt) < 1` , which entails that A(t) will be between A(0) and G